Oblicz pracę wyjścia dla metalu który długość graniczna promieniowania wynosi 6 x 10 do -7 m
h = 6,63 x 10⁻³⁴Js
c = 3 x 10⁸m/s
λ = 6 x 10⁻⁷m
E = W = hc/λ
W = 6,63 x 10⁻³⁴Js x 3 x 10⁸m/s / 6 x 10⁻⁷m = 3,315 x 10⁻¹⁹J ≈ 2eV
----------------------------------------------------------------------------------------------------------
Feci, quod potui, faciant meliora potentes
Pozdrawiam :)
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
h = 6,63 x 10⁻³⁴Js
c = 3 x 10⁸m/s
λ = 6 x 10⁻⁷m
E = W = hc/λ
W = 6,63 x 10⁻³⁴Js x 3 x 10⁸m/s / 6 x 10⁻⁷m = 3,315 x 10⁻¹⁹J ≈ 2eV
----------------------------------------------------------------------------------------------------------
Feci, quod potui, faciant meliora potentes
Pozdrawiam :)