Odpowiedź:
[tex]\frac{(\frac{7}{10}-1)(4\frac{1}{3}-3,5)}{1\frac{3}{4}}=\frac{-\frac{3}{10}*\frac{5}{6}}{\frac{7}{4}}=\frac{-\frac{1}{4}}{\frac{7}{4}}=-\frac{1}{4}*\frac{4}{7}=-\frac{1}{7}[/tex]
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Odpowiedź:
[tex]\frac{(\frac{7}{10}-1)(4\frac{1}{3}-3,5)}{1\frac{3}{4}}=\frac{-\frac{3}{10}*\frac{5}{6}}{\frac{7}{4}}=\frac{-\frac{1}{4}}{\frac{7}{4}}=-\frac{1}{4}*\frac{4}{7}=-\frac{1}{7}[/tex]