Oblicz pH roztworu cuso4 zawierającego 5 g tej soli w 50 cm3
ms=5g
M=160g
v=0,05dm3
n=m/M
n=0,03125mola
Cm=n/v
Cm=0,625mola
pH=-log[0,625]=0,2
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ms=5g
M=160g
v=0,05dm3
n=m/M
n=0,03125mola
Cm=n/v
Cm=0,625mola
pH=-log[0,625]=0,2