Oblicz pH 0.01-molowego roztworu zasady sodowej.
NaOH--->Na+ + OH-0,01 0,01
pOH=-log 0,01=2pH=14-2=12pH wynosi 12
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
NaOH--->Na+ + OH-
0,01 0,01
pOH=-log 0,01=2
pH=14-2=12
pH wynosi 12