Oblicz opór zastępczy oporników połączonych według schematu.R1=3om
R2=R3=2om
R4=4om
R5=1omPROSZĘ O POMOC, PILNIE !!
R2,3,4= (1/R2)+(1/R3)+(1/R4)=(1/2)+(1/2)+(1/4)=1,25 ohmaR1,2,3,4,5=R1+R2,3,4+R5=3+1,25+1=5,25 ohma
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R2,3,4= (1/R2)+(1/R3)+(1/R4)=(1/2)+(1/2)+(1/4)=1,25 ohma
R1,2,3,4,5=R1+R2,3,4+R5=3+1,25+1=5,25 ohma