Oblicz opór zastępczy, jeżeli R1=R2=R3=R4=2 Ω
More Questions From This User See All
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
R1+R2+R3-wszystkie szeregowo
2+2+2=6 om
C)
R3+R4=2+2=4
R34+R2/R34*R2
4+2/4*2=6/8
=0,75
R234+R1/R234*R1
0,75+2/0,75*2=2,75/1,5
=1,83 om
D)
R2+R3=2+2=4
R1+R23/R1*R23
2+4/2*4=6/8
=0,75 om