Odpowiedź:
szeregowo:
R = R1 + R2 = 2+5 = 7 Ω
równolegle:
R = (R1*R2)/(R1+R2) = (2*5)/(2+5) = 10/7 Ω = 1 i 3/7 Ω
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Odpowiedź:
szeregowo:
R = R1 + R2 = 2+5 = 7 Ω
równolegle:
R = (R1*R2)/(R1+R2) = (2*5)/(2+5) = 10/7 Ω = 1 i 3/7 Ω