oblicz opór zastępczy 3 odbiornikow połączonych rownolegle o oporach R1=10om R2=20om R3=40om
1/R = 1/10Ω + 1/20Ω + 1/40Ω = (4+2+1)/40Ω = 7/40Ω
7R = 40Ω |:7
R = 5i5/7Ω w zaokrągleniu 5,71Ω
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1/R = 1/10Ω + 1/20Ω + 1/40Ω = (4+2+1)/40Ω = 7/40Ω
7R = 40Ω |:7
R = 5i5/7Ω w zaokrągleniu 5,71Ω