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interpretacja molowa:
4mole Li-- 1mola O2-- 2moli Li2O
Dane: mLi2O=100g
Szukane: VO2=?
MLi2O=2*7g/mol+16g/mol=30g/mol
22,4dm3 O2---- 2*30g Li2O
x dm3 O2 ---- 100g Li2O
x=37,3dm3
Odp. Potrzebne jest 37,3dm3 tlenu.