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objętośc tlenu: 24*0,21=5,04
objętość azotu: 24*0,78= 18,72
V= 3 x 2 x 4
V= 24 m3
(azot)- 78% x 24 m3 = 78/100 x 24 m3= 18,72 m3
(tlen)- 21% x 24 m3 = 21/100 x 24 m3 = 5,04 m3
AZOTU:
24m sześcienne*78,08 %= 18,7392
TLENU:
24m sześcienne*20,95%=5,028