Odpowiedź: 268,8dm3 tlenu
3*22,4dm3 2mole
4Al + 3O2 -->2Al2O3
x 8moli
67,2dm3 --------2mole
x -------- 8moli
x= 67,2dm3* 8moli/2mole
x=268,8dm3
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Odpowiedź: 268,8dm3 tlenu
3*22,4dm3 2mole
4Al + 3O2 -->2Al2O3
x 8moli
67,2dm3 --------2mole
x -------- 8moli
x= 67,2dm3* 8moli/2mole
x=268,8dm3