mC3H5(OH)3=92umO2=32u2C3H5(OH)3 + O2 ----> 6C + 8H2O184g glicerolu ------ 32g tlenu100g glicerolu ------ xg tlenux = 17,39g tlenum=17,39gd=1,43g/dm3v=m/dv=17,39/1,43v = 12,16dm3 tlenu
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mC3H5(OH)3=92u
mO2=32u
2C3H5(OH)3 + O2 ----> 6C + 8H2O
184g glicerolu ------ 32g tlenu
100g glicerolu ------ xg tlenu
x = 17,39g tlenu
m=17,39g
d=1,43g/dm3
v=m/d
v=17,39/1,43
v = 12,16dm3 tlenu