[tex]Dane:\\t = 1,5 \ min = 1,5\cdot 60 \ s = 90 \ s\\s = 1,5 \ m\\F = 200 \ N\\Szukane:\\P = ?[/tex]
Rozwiązanie
Z definicji mocy:
[tex]P = \frac{W}{t}\\\\W = F\cdot s, \ zatem:\\\\P = \frac{F\cdot s}{t}[/tex]
Podstawiamy wartości:
[tex]P = \frac{200 \ N\cdot 1,5 \ m}{90 \ s}=\frac{300 \ J}{90 \ s}\\\\\boxed{P = 3,(3) \ W\approx3,3 \ W}[/tex]
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[tex]Dane:\\t = 1,5 \ min = 1,5\cdot 60 \ s = 90 \ s\\s = 1,5 \ m\\F = 200 \ N\\Szukane:\\P = ?[/tex]
Rozwiązanie
Z definicji mocy:
[tex]P = \frac{W}{t}\\\\W = F\cdot s, \ zatem:\\\\P = \frac{F\cdot s}{t}[/tex]
Podstawiamy wartości:
[tex]P = \frac{200 \ N\cdot 1,5 \ m}{90 \ s}=\frac{300 \ J}{90 \ s}\\\\\boxed{P = 3,(3) \ W\approx3,3 \ W}[/tex]