Oblicz masy molowe oraz stosunki masowe.
a) CuO
b) K Cl
c) Mg Br²
d) Mn² O³
a) M CuO = 64 + 16 = 80g/mol
m Cu : m O = 64 : 16 = 4: 1
b) M KCl = 39 + 35,5 = 74,5g/mol
m K : m Cl = 39 : 35,5
c) M MgBr2 = 24 + 2*80 = 184g/mol
m Mg : m Br = 24 : 160 = 3 : 20
d) M Mn2O3 = 2*55 + 3* 16 = 158g/mol
m Mn : m O = 110 : 48 = 55 : 24
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a) M CuO = 64 + 16 = 80g/mol
m Cu : m O = 64 : 16 = 4: 1
b) M KCl = 39 + 35,5 = 74,5g/mol
m K : m Cl = 39 : 35,5
c) M MgBr2 = 24 + 2*80 = 184g/mol
m Mg : m Br = 24 : 160 = 3 : 20
d) M Mn2O3 = 2*55 + 3* 16 = 158g/mol
m Mn : m O = 110 : 48 = 55 : 24