Question

Oblicz masy:
Fe(OH)3
Al2(SO4)3
Ca(OH)2
H3PO4
Cu2O
Sn(OH)2

Answer 1

Fe(OH)3 = 56 + 48 + 3 = 107 u
Al2(SO4)3 = 54 + 32 + 192 = 278 u
Ca(OH)2 = 40 + 2 + 32 = 74 u
H3PO4 = 3 + 64 + 31 = 98 u
Cu2O = 16 + 127 = 143 u
Sn(OH)2 = 2 + 32 + 119 = 153 u

Answer 2

Fe(OH)3=Fe+3o+3H=56+3x16+3x1=56+3+48=107

Al2(SO4)3=Al2+S3+O12=2x27+3x32+12x16=96+54+192=342

Ca(OH)2=40+2x16+2=42+32=74

H3PO4=3x1+31+4x16=64+34=98

Cu2O=2x64+16=128+16=144

Sn(OH)2=119+32+2=34+119=153


Licze na naj ;)