oblicz masy cząsteczkowe (w unitach)
Cu(OH)2
Cl2 (chlor)
(NH4)2CO3
Cu(OH)2
Cl2 (chlor)
(NH4)2CO3
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mCu(OH)2=63,5u+2*16u+2*1u=97,5 u
mCl2=2*35,5u=71 u
m(NH4)2CO3=2*14u+8*1u+12u+3*16u=96 u
Odpowiedź:
mCu(OH)2= 64u+ 32u+ 2u÷= 98u
mCl2= 2 × 35,5=71u
(NH4)2CO3= 2×14u+ 8×1u+ 12u+ 48u=28u+ 8u+ 12u+ 48u= 96u
Wyjaśnienie: