Odpowiedź:
mP4= 4×31u= 124u
mN2O= 2×14u+ 16u= 28u+ 16u= 44u
mFe2O3= 2×56u+ 3×16u= 112u+ 48u= 160u
mCa(OH)2= 40u+ 2×16u+ 2×1u= 40u+ 32u+ 2u= 74u
mMg3(PO4)2= 3×24u+ 2× 31u+ 8×16u= 72u+ 62u+ 128u= 262u
Wyjaśnienie:
1. P4 = 30,974 x 4 = 123.896(u)
2.N2O = (14,07x2) + 15.999 = 44.139(u)
3. Fe2O3 = ( 15.999 x3) + (55,845 x 2) =159.687(u)
4.Ca(OH)2 = 40.078 + 2,016 + 31.998= 74.092(u)
5.MG3(PO4)2 = (24.305 x 3) + 2(30.974 + 15.999 x 4) = 262.855(u)
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Odpowiedź:
mP4= 4×31u= 124u
mN2O= 2×14u+ 16u= 28u+ 16u= 44u
mFe2O3= 2×56u+ 3×16u= 112u+ 48u= 160u
mCa(OH)2= 40u+ 2×16u+ 2×1u= 40u+ 32u+ 2u= 74u
mMg3(PO4)2= 3×24u+ 2× 31u+ 8×16u= 72u+ 62u+ 128u= 262u
Wyjaśnienie:
Odpowiedź:
1. P4 = 30,974 x 4 = 123.896(u)
2.N2O = (14,07x2) + 15.999 = 44.139(u)
3. Fe2O3 = ( 15.999 x3) + (55,845 x 2) =159.687(u)
4.Ca(OH)2 = 40.078 + 2,016 + 31.998= 74.092(u)
5.MG3(PO4)2 = (24.305 x 3) + 2(30.974 + 15.999 x 4) = 262.855(u)
Wyjaśnienie: