Oblicz masy cząsteczkowe podanych związków chemicznych:
a. m Na2CO3 =
b. m Al2(SO4)3 =
m Na2CO3
2Na= 23u * 2= 46u
C= 12u
3O= 3 * 16u= 48u
46u + 12u + 48 u =106 u
m Al2(SO4)3
2 Al= 27u * 2= 54u
3 S= 32u * 3= 96 u
12 O= 12 * 16u= 192 u
54u + 96u + 192u = 342u
a)
m(Na₂CO₃)=2·23u+12u+3·16u=46u+12u+48u=106u
b)
m(Al₂(SO₄)₃)=2·27u+3·32u+12·16u=54u+96u+192u=342u
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m Na2CO3
2Na= 23u * 2= 46u
C= 12u
3O= 3 * 16u= 48u
46u + 12u + 48 u =106 u
m Al2(SO4)3
2 Al= 27u * 2= 54u
3 S= 32u * 3= 96 u
12 O= 12 * 16u= 192 u
54u + 96u + 192u = 342u
a)
m(Na₂CO₃)=2·23u+12u+3·16u=46u+12u+48u=106u
b)
m(Al₂(SO₄)₃)=2·27u+3·32u+12·16u=54u+96u+192u=342u