Question

Oblicz masy cząsteczkowe podanych związków chemicznych:

- mCuO =
- mFe2O3 =
- mNa2CO3 =
- mH2SO4 =
- mCa(OH)2 =
- mFe2(SO3)3 =

Proszę o pomoc

Answer 1

- mCuO=63,5u+16u=79,5u
- mFe2O3=2*56u+3*16u=160u
- mNa2CO3=2*23u+12u+3*16u=106u
- mH2SO4=2*1u+32u+4*16u=98u
- mCa(OH)2=40u+2*16u+2*1u=74u
- mFe2(SO3)3=2*56u+3*32u+9*16u=352u

Answer 2

MCuO = 64u+16u = 80u
mFe2O3 = 2*56u+3*16u = 112u+48u = 160u
mNa2CO3 = 2*23u+12u+3*16u = 46u+12u+48u = 106u
mH2SO4 = 2*1u+32u+4*16u = 2u+32u+64u = 98u
mCa(OH)2 = 40u+2*16u+2*1u = 40u+32u+2u = 74u
mFe2(SO3)3 = 2*56u+3*32u+9*16u = 112u+96u+144u = 352u