Oblicz masy cząsteczkowe podanych wodorotlenków
Mg(OH)₂ ,Fe(OH)₃, KOH.
Mg(OH)₂ ,Fe(OH)₃, KOH.
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Masa Fe(OH)₃= 56 + 3*16 + 3*1= 56+48+3=107u
Masa KOH= 39 +16+1=56u
24u+2x16u+2x1u=58u
Fe(OH)₃
56u+3x16u+3x1u=107u
KOH
39u+16u+1u=56u