Question

Oblicz masy cząsteczkowe podanych substancji:

Cl2 , P4, KBr, H2S, NH3, Na2SO4, (NH4)CO3, Mg3, (PO4)2, MgO, NaF, CaO, H2SO4

DAM NAJ :)

Answer 1

m Cl₂ = 2 · 35,5u = 71u

m P₄ = 4 · 31u = 124u

m KBr = 39u + 80u = 119u

m H₂S = 2 · 1u + 32u = 34u

m NH₃ = 14u + 3 · 1u= 17u

m Na₂SO₄ = 2 · 23u + 32u + 4 · 16 = 142u

m (NH₄)CO₃ = 14u + 4 · 1u + 12u + 2 · 16u = 62u

m Mg₃ = 3 · 24u = 72u

m (PO₄)₂ = 2 · 31u + 2 · 4 · 16u = 190u

m MgO = 24u + 16u = 40u

m NaF = 23u + 19u = 42u

m CaO = 40u + 16u = 56u

m H₂SO₄ = 2 · 1u + 32u + 4 · 16u = 98u

Answer 2

mCl2=2*35,5= 71

mP4=P*4=31*4=124

mKBr=mK*mBr=40+80=120

mH2S=mH*(2*mS)=1*(2*32)=65

mNh3=mH*3+mN=3+14=17

mNa2S04=2*mNa+mS+mO*4=142

m(NH4)CO3=mN+nH*4+mC+mO*3=14+4+12+48=78

mMg3=mMg*3=24*3=72

mMgo=mMg+mO=24+16=40

m(PO4)2=mP*2+mo*4*2=31*2+16*2*4=190

mNaF=mNa+mF=23+19=51

mCa0=mCa+m0=40+16=56

mH2SO4=mH*2+mS+mO*4=1*2+32+16*4=98