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etanol - C2H5OH
masa cząsteczkowa CH3OH = 12u+3*1u+16u+1u= 32u
masa cząsteczkowa C2H5OH = 2*12u+5*1u+16u+1u= 46u
Odp. Masa cząsteczkowa metanolu wynosi 32u, a etanolu 46u.
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