oblicz masy czasteczkowe nastepujacych substacji:H2SO3,Cl2O7,P4
H2SO3
2+32+(3x16)=82u
Cl2O7
(2 x 35,5) + (7x16)=183u
P4
31x4=124u
MH = 1u
MS= 32u
MO= 16u
MP= 31u
MCl= 35,5u
H₂SO₃ = 2MH + MS + 3MO = 2 + 32 + 3×16 = 34 + 48 = 82u
Cl₂O₇ = 2MCl + 7MO = 2 × 35,5 + 7 × 16 = 70 +112 = 183u
P₄ = 4MP = 4 × 31 = 124u
mH₂SO₃=2 x 1u + 1 x 32u + 3 x 16u=82u
mCl₂O₇= 2 x 35,5u + 7 x 16u =183u
mP₄= 4 x 31u=124u
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H2SO3
2+32+(3x16)=82u
Cl2O7
(2 x 35,5) + (7x16)=183u
P4
31x4=124u
MH = 1u
MS= 32u
MO= 16u
MP= 31u
MCl= 35,5u
H₂SO₃ = 2MH + MS + 3MO = 2 + 32 + 3×16 = 34 + 48 = 82u
Cl₂O₇ = 2MCl + 7MO = 2 × 35,5 + 7 × 16 = 70 +112 = 183u
P₄ = 4MP = 4 × 31 = 124u
mH₂SO₃=2 x 1u + 1 x 32u + 3 x 16u=82u
mCl₂O₇= 2 x 35,5u + 7 x 16u =183u
mP₄= 4 x 31u=124u