Oblicz masy atomów :
Fe (OH)3 =
AlCl3 =
K2SO4 =
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Oblicz masy atomów :
Fe (OH)3 =
AlCl3 =
K2SO4 =
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Fe = 56
O = 16
H = 1
Al = 27
Cl = 35
K = 39
S = 32
Fe(OH)₃ = 56 + 3*(16 + 1) = 56 + 3 * 17 = 56 + 51 = 107
AlCl₃ = 27 + 3 * 35 = 27 + 105 = 132
K₂SO₄ = 2 * 39 + 32 + 4 * 16 = 78 + 32 + 64 = 174
Fe (OH)3 = 56 + 3 X16 +3X1=56+48+3=107
AlCl3 = 27+35X3=27+105=132
K2SO4 =39X2+32+4X16=78+32+64=174