mCH3COOH=12+3+13+2*16+1=32+15+14=60gdla wegla60g---100%24g---x% x=2400/60=40%dla tlenu60g---100%32---y% y=3200/60=53,33%dla wodoru60g---100%4g---z% z=400/60=6,66%
mC = 12u
mO = 16u
mH = 1u
%C = (2 · 12u · 100%) : (2 · 12u + 2 · 16u + 4 · 1u) = 2400 : 60 = 40%
%O = (2 · 16u · 100%) : (2 · 12u + 2 · 16u + 4 · 1u) = 3200 : 60 = 53,33%
%H = (4 · 1u · 100%) : (2 · 12u + 2 · 16u + 4 · 1u) = 400 : 60 = 6,67%
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mCH3COOH=12+3+13+2*16+1=32+15+14=60g
dla wegla
60g---100%
24g---x% x=2400/60=40%
dla tlenu
60g---100%
32---y% y=3200/60=53,33%
dla wodoru
60g---100%
4g---z% z=400/60=6,66%
mC = 12u
mO = 16u
mH = 1u
%C = (2 · 12u · 100%) : (2 · 12u + 2 · 16u + 4 · 1u) = 2400 : 60 = 40%
%O = (2 · 16u · 100%) : (2 · 12u + 2 · 16u + 4 · 1u) = 3200 : 60 = 53,33%
%H = (4 · 1u · 100%) : (2 · 12u + 2 · 16u + 4 · 1u) = 400 : 60 = 6,67%