Question

Oblicz % masowy pierwiastków chemicznych w propanolu.

Answer 1

C3H7OH-(12u*3)+(1u*8)+(16u*1)=36u+8u+16u=60u

%C=36x100%/60=60%

%O=16x100%/60=26,7%

%H=8x100%/60=13,3%

Answer 2

Masa C3H7OH=3x12u+8x1u+1x16u=60u
%C=36x100%/60=60%
%O=16x100%/60=26,7%
%H=8x100%/60=13,3%