Question

oblicz mase wodorotlenku sodu i mase wodoru ktore powstana w reakcji 11,5 g sodu z woda. Na+h20--> n2oh+h2

Answer 1

2Na + 2H2O = 2NaOH + H2

 

MNa = 2 mole * 23g/mol = 46g

MNaOH = 2 mole * 40g/mol = 80g 

mNa = 11,5g

mNaOH = (11,5g * 80g)/46g = 20g tyle powstanie wodorotlenku sodu

 

MH2 = 2 g/mol * 1 mol = 2g

mH2 = (2g * 11,5g)/46g = 0,5g tyle powstanie wodoru