Oblicz mase roztworu, ktorego stezenie wynosi 25% , a substancja zawarta w roztworze ma mase 30g
Cp=25%
ms=30g
Cp=ms/mr *100%
Cp=ms/mr => mr=ms*100%/Cp
mr=30*100%/25%=120 [g]
ms - masa substancji
mr - masa roztworu
cp - stężenie procentowe
ms - 30g
mr - ?
cp - 25%
ms * 100%
Cp = -------------
mr
mr = ---------------
Cp
30g * 100%
mr = -------------- = 120g
25%
mr = 120g
Odp. Masa tego roztworu wynosi 120g.
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Cp=25%
ms=30g
Cp=ms/mr *100%
Cp=ms/mr => mr=ms*100%/Cp
mr=30*100%/25%=120 [g]
ms - masa substancji
mr - masa roztworu
cp - stężenie procentowe
ms - 30g
mr - ?
cp - 25%
ms * 100%
Cp = -------------
mr
ms * 100%
mr = ---------------
Cp
30g * 100%
mr = -------------- = 120g
25%
mr = 120g
Odp. Masa tego roztworu wynosi 120g.