Question

oblicz mase molową i cząsteczkową :
1.Mg(OH)2
2.H3Po4
3.KCL​

Answer 1

Verified answer

1) M Mg(OH)2=24 g/mol+2*16 g/mol+2*1 g/mol=58 g/mol

mMg(OH)2=24 u+2*16 u+2*1 u=58 u

2) M H3PO4=3*1 g/mol+31 g/mol+4*16 g/mol=98 g/mol

mH3PO4=3*1 u+31 u+4*16 u=98 u

3) M KCl=39 g/mol+35,5 g/mol=74,5 g/mol

mKCl=39 u+35,5 u=74,5 u

Answer 2

Odpowiedź:

1. M = 16*2+2+24 = 58g (masa molowa)

m = 58 u (masa cząsteczkowa)

2. M = 16*4+31+3 = 98g

m = 98u

3. M = 39+35.5 = 74.5g

m = 74.5