oblicz mase kwasu solnego konieczna do uzyskania 4 moli chlorku cynku w reakcji kwasu z metalem . Pilne ! prosze o rozwiaznie .
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mHCl=36,5u
Zn + 2HCl---->ZnCl2 + H2
73g HCl--------1mol ZnCl2
xg HCl----------4mole ZnCl2
x = 292g HCl
M(HCl)=1g+35,5g=36,6g
2HCl+Zn-->ZnCl2+H2
2*36,5g-----1mol
xg------------4mol
xg=73g*4mol/1mol
xg=292g