Oblicz mase cząsteczkową wodorotlenków : potasu, wapnia, sodu.
mCa(OH)₂ = 40u+2*16u+2*1u = 74umNaOH = 23u+16u+1u = 40umKOH = 39u+16u+1u = 56u
NaOH=23+16+1
mNaOH=40u
mKOH=39+16+1
mKOH=56u
mCa(OH)2=40+2*16+2*1
mCa(OH)2=74u
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mCa(OH)₂ = 40u+2*16u+2*1u = 74u
mNaOH = 23u+16u+1u = 40u
mKOH = 39u+16u+1u = 56u
NaOH=23+16+1
mNaOH=40u
mKOH=39+16+1
mKOH=56u
mCa(OH)2=40+2*16+2*1
mCa(OH)2=74u