Question

Oblicz mase czasteczkowa podanych alkenów : C2H4, C3H6 , C4H8 , C5H10,C6H12, C7H14 , C8H16, C9H18,C10H20

Answer 1

C2H4= 12*2 + 1*4=24+4=28
C3H6= 12*3+1*6=36+6=42
C4H8= 12*4+1*8=48+8=56
 C5H10=12*5+1*10=60+10=70
C6H12=12*6+1*12=72+12=84
C7H14=12*7+1*14=84+14=98
C8H16= 12*8+1*16=96+16=112
C9H18=12*9+1*18=108+18=126
C10H20=12*10+1*20+120+20=140

Answer 2

1) 12*2 + 1*4=24+4=28
2) 12*3+1*6=36+6=42
   12*4+1*8=48+8=56
   12*5+1*10=60+10=70
12*6+!*12=72+12=84
12*7+1*14=84+14=98
12*8+1*16=96+16=112
12*9+1*18=108+18=126
12*10+1*20+120+20=140