A1 = 69
A2 = 71X1 = 60,2%X2 = 39,8%m at. = ?
Korzystam z równania na średnią masą atomowąm at. = A1*X1% + A2*X2%/100% m at. = 69*60,2% + 71*39,8/100%m at. = 4153,8 + 2825,8/100
m at. = 6979,6/100
m at. = 69,796u
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A1 = 69
A2 = 71
X1 = 60,2%
X2 = 39,8%
m at. = ?
Korzystam z równania na średnią masą atomową
m at. = A1*X1% + A2*X2%/100%
m at. = 69*60,2% + 71*39,8/100%
m at. = 4153,8 + 2825,8/100
m at. = 6979,6/100
m at. = 69,796u