oblicz mase atomowa i czasteczkowa dla 3Fe, 3CO(2-pierwiastek) i H(2)O. daje naj
3Fe:
MFe - 56 u
Ma3Fe = 3 razy 56 u = 168 u
3CO2:
MC - 12 u
MO - 16u
Mcz3CO2 = 3 razy 12 u + 6 razy 16 u = 132u
H2O
MH - 1u
MO - 16 u
MaH2O = 2 razy 1u + 16 u = 18 u
Tyle :)
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3Fe:
MFe - 56 u
Ma3Fe = 3 razy 56 u = 168 u
3CO2:
MC - 12 u
MO - 16u
Mcz3CO2 = 3 razy 12 u + 6 razy 16 u = 132u
H2O
MH - 1u
MO - 16 u
MaH2O = 2 razy 1u + 16 u = 18 u
Tyle :)