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MCaO = 40 + 16 = 56 g/mol
nCaO = 25/56 = 0,45 mol
obj. molowa gazów w war. normalnych: 22,4 dm3/mol
vCO2 = 15 dm3
nCO2 = 15/22,4 = 0,67 mol
mamy nadmar CO2
powstanie 0,45 mol CaCO3
MCaCO3 = 40 +12 + 3*16 = 100 g/mol
mCaCO3 = 0,45 * 100 = 45g
Odp. powstanie 45 g CaCO3