Question

Oblicz masę następujących cząsteczek:

Mg(OH)2

HNO3

Ca(NO3)2

CH3COOH

Answer 1

mMg(OH)2 = mMg + 2 mo + 2 mH =  24u + 2*16u + 2*1u = 58u

mMg(OH)2 =58u

 

mHNO3 = mH +  mN + 3 mO = 1u +14u + 3*16u = 63u

mHNO3 =63u

 

mCa(NO3)2 = mCa + 2 mN + 6 mO =40u + 2*14u + 6*16u = 164u

mCa(NO3)2 = 164u

 

mCH3COOH =2 mC + 2 mO + 4 mH =2*12u + 2*16u + 4*1u = 60u

mCH3COOH = 60u

Answer 2

M Mg=24g/mol

M O= 16g/mol

M H= 1g/mol

M N= 14g/mol

MCa = 40 g/mol

 

 

M Mg(OH)2 = 24g + (1g + 16g)*2=58g/mol

M HNO3 = 1g + 14g+ 3*16g= 63g/mol

M Ca(NO3)2= 40g + (14g+3*16g)*2= 164g/mol

M CH3COOH = 2*12g + 4*1g+2*16g= 60g/mol