Oblicz masę kwasu siarkowego (VI) potrzebną do zobojętnienia 0,015 mola wodorotlenku glinu
M H2SO4 = 98 g/mol
M Al(OH)3 = 78 g/mol
78 -> 1 mol
x -> 0,015 mola
x = 1,17 [g]
98 -> 78
y -> 1,17
y = 1,47[g]
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M H2SO4 = 98 g/mol
M Al(OH)3 = 78 g/mol
78 -> 1 mol
x -> 0,015 mola
x = 1,17 [g]
98 -> 78
y -> 1,17
y = 1,47[g]