oblicz masę kwasu mrówkowego,jaka wyjdzie w reakcji z 2,3 g metanolu w celu otrzymania mrówczanu metylu
HCOOH+CH3OH-->HCOOCH3+H2O
mCH3OH=2,3g
mCH3OH=32u
mHCOOH=46u
2,3g-x
32u-46u
x=3,3g HCOOH
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HCOOH+CH3OH-->HCOOCH3+H2O
mCH3OH=2,3g
mCH3OH=32u
mHCOOH=46u
2,3g-x
32u-46u
x=3,3g HCOOH