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2 K+ H2O ----> 2KOH + H2
30g. x
78g -112g
30g-x
x= 43,08g
Masa KOH to 43,08g
2K + 2 H₂O ------> 2KOH + H₂
m2K = 2 * 39u = 78u
m2KOH = 2 * 39u + 2 * 16u + 2 * 1u = 78u + 32u + 2u = 112u
układamy proporcję
78u K ------------------- 112u KOH
30g K ------------------- x
x = 30g * 112u / 78u
x = 43,1g KOH
Powstanie 43,1g KOH