Oblicz masę cząsteczkową:
1.
2.
a)
m((NH₄)₃PO₄)=3·14u+12·1u+31u+4·16u=42u+12u+31u+64u=149u
b)
m(Fe₂(SO₃)₃)=2·56u+3·32u+9·16u=112u+96u+144u=352u
1. 3*14+12*1+31+4*16= 149 g/mol
2. 56*2+32*3+ 16*9=352 g/mol
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
a)
m((NH₄)₃PO₄)=3·14u+12·1u+31u+4·16u=42u+12u+31u+64u=149u
b)
m(Fe₂(SO₃)₃)=2·56u+3·32u+9·16u=112u+96u+144u=352u
1. 3*14+12*1+31+4*16= 149 g/mol
2. 56*2+32*3+ 16*9=352 g/mol