Oblicz masę cząsteczkową skład % i stosunek H : S : O w H2SO4
m(H₂SO₄)=2·1u+32u+4·16u=2u+32u+64u=98u
m(H₂)=2u
m(S)=32u
m(O₄)=64u
%H=2u/98u·100%≈2,04%
%S=32u/98u·100%≈32,65%
%O=64u/98u·100%≈65,31%
H:S:O=2u:32u:64u=2:32:64=1:16:32
mH = 2 * 1u = 2u
mS= 1 * 32u = 32u
mO= 4 * 16u = 64u
mH2SO4 = 2u + 32 u + 64u = 98u
%H = 2u/98u * 100% = 2%
%S = 32u/98u * 100% = 33%
%O = 64u/98u * 100% = 65%
stosunek masowy: H:S:0 ---> 2:32:64 = 1:16:32
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m(H₂SO₄)=2·1u+32u+4·16u=2u+32u+64u=98u
m(H₂)=2u
m(S)=32u
m(O₄)=64u
%H=2u/98u·100%≈2,04%
%S=32u/98u·100%≈32,65%
%O=64u/98u·100%≈65,31%
H:S:O=2u:32u:64u=2:32:64=1:16:32
mH = 2 * 1u = 2u
mS= 1 * 32u = 32u
mO= 4 * 16u = 64u
mH2SO4 = 2u + 32 u + 64u = 98u
%H = 2u/98u * 100% = 2%
%S = 32u/98u * 100% = 33%
%O = 64u/98u * 100% = 65%
stosunek masowy: H:S:0 ---> 2:32:64 = 1:16:32