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MmolCO2= 12g + 2*16g =44g/mol
mCO2 = 12 + 2 * 16 = 44u
b)
mMgO=24u+16u=40u
MmolMGO= 16g +24g= 40g/mol
c)
mAl₂S₃=2*27u+3*32u=54u+96u=150u
MmolAl₂S₃= 2*27+ 3*32=150g/mol
mCO₂ = 12u + 2 * 16u = 44u masa cząsteczkowa
MCO₂ = 44 g/mol masa molowa
b)tlenku magnezu
mMgO = 24u + 16u = 40u
MMgO = 40 g/mol
c)siarczku glinu
mAl₂S₃ = 27u * 2 + 32u * 3 = 54u + 96u = 150u
MAl₂S₃ = 150 g/mol