a) m 3 H2O2=3*(2*1u+2*16u)=102u
b) m 7 Cu=7*63,5u=444,5u
c) m 7 CuO=7*(63,5u+16u)=556,5u
d) m 12 Fe2O3=12*(2*56u+3*16u)=1920u
e) m 4 HCl=4*(1u+35,5u)=146 u
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a) m 3 H2O2=3*(2*1u+2*16u)=102u
b) m 7 Cu=7*63,5u=444,5u
c) m 7 CuO=7*(63,5u+16u)=556,5u
d) m 12 Fe2O3=12*(2*56u+3*16u)=1920u
e) m 4 HCl=4*(1u+35,5u)=146 u