Oblicz masę cząsteczkową:
2Fe(OH)3
6O2
4SiO2
2 Fe(OH)3 = 2* ( 56u + 3* 17u) = 2 * 107u = 214u
6O2 = 6*(16u*2)= 6*32u = 192u
4 SiO2 = 4* ( 28u + 2*16u) = 4* 60u = 240u
2Fe(OH)3=2*56u+6*16u+6*1u=112u+96u+6u=214u
6O2=12*16u=192u
4SiO2=4*28u+8*16u=112u+128u=240u
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2 Fe(OH)3 = 2* ( 56u + 3* 17u) = 2 * 107u = 214u
6O2 = 6*(16u*2)= 6*32u = 192u
4 SiO2 = 4* ( 28u + 2*16u) = 4* 60u = 240u
2Fe(OH)3=2*56u+6*16u+6*1u=112u+96u+6u=214u
6O2=12*16u=192u
4SiO2=4*28u+8*16u=112u+128u=240u