Oblicz masę cząsteczkową :
1) Fe2(SO4)3
2)Mg (Oh)2
3)cA(no3)2
1) 56*2+3(32+16*4)=112+288=400u
2) 24+2(16+1)= 58u
3) 40+2(14+3*14)= 40+124=164u
1) Fe2(SO4)3 = 2* 56u + 3* [ 32u + 68u] = 112u + 300u= 412u2) Mg(OH)2= 2*[1u + 16u] + 24u = 58u 3) Ca(NO3)2= 40u + 2*[14u + 48u]= 40u + 2 * 62u= 164u
Pozdrawiam, kate66 ;)
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1) 56*2+3(32+16*4)=112+288=400u
2) 24+2(16+1)= 58u
3) 40+2(14+3*14)= 40+124=164u
1) Fe2(SO4)3 = 2* 56u + 3* [ 32u + 68u] = 112u + 300u= 412u
2) Mg(OH)2= 2*[1u + 16u] + 24u = 58u
3) Ca(NO3)2= 40u + 2*[14u + 48u]= 40u + 2 * 62u= 164u
Pozdrawiam, kate66 ;)