Oblicz masę czosteczkową następujących substancji:
A) Mg3(PO4)2
B) Fe2(SO4)3
Sorki że bez indeksów!
a)
m(Mg₃(PO₄)₂)=3·24u+2·(31u+4·16u)=72u+2·(31u+64u)=72u+2·95u=72u+190u=262u
b)
m(Fe₂(SO₄)₃)=2·56u+3·(32u+4·16u)=112u+3·(32u+64u)=112u+3·96u=112u+288u=400u
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a)
m(Mg₃(PO₄)₂)=3·24u+2·(31u+4·16u)=72u+2·(31u+64u)=72u+2·95u=72u+190u=262u
b)
m(Fe₂(SO₄)₃)=2·56u+3·(32u+4·16u)=112u+3·(32u+64u)=112u+3·96u=112u+288u=400u