oblicz masę cynku potrzebną do wydzielenia z kwasu solnego 200dm3 wodoru
help!!! to na jutro!!!
2HCl + Zn ----> ZnCl2 + H2
65g Zn ---- 22,4dm3 H2
X --- 200dm3
X=580g Zn
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2HCl + Zn ----> ZnCl2 + H2
65g Zn ---- 22,4dm3 H2
X --- 200dm3
X=580g Zn