Oblicz masę atomową boru, wiedząc że naturalna mieszanina zawiera 18,3% izotopu ¹⁰Bi, 81,7% izotopu ¹¹Bi
M= (10*18,3+11*81,7)/100
M= (183+ 898,7) /100
M= 1081,7 /100
M= 10,817u
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M= (10*18,3+11*81,7)/100
M= (183+ 898,7) /100
M= 1081,7 /100
M= 10,817u