a) M Mg=24g/mol, więc 2*24g=48gb) M O=16g/mol, więc 4*16g=64gc) M O2=32g/mol, więc 4*32g=128gd) M H2SO3=82g/mol, więc 6*82g=492ge) M Fe(OH)3=107g/mol, więc 7*107=749gf) M Fe2(SO3)3=352g/mol, więc 8*352=2816g
Pozdrawiam.
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a) M Mg=24g/mol, więc 2*24g=48g
b) M O=16g/mol, więc 4*16g=64g
c) M O2=32g/mol, więc 4*32g=128g
d) M H2SO3=82g/mol, więc 6*82g=492g
e) M Fe(OH)3=107g/mol, więc 7*107=749g
f) M Fe2(SO3)3=352g/mol, więc 8*352=2816g
Pozdrawiam.