Oblicz masę 3 moli kwasu siarkowego VI o wzorze H2SO4
M H2SO4= 2*1u + 32u+ 4* 16u= 98u
1 mol H2SO4 - 98u
3 mole - x u
x=294u
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M H2SO4= 2*1u + 32u+ 4* 16u= 98u
1 mol H2SO4 - 98u
3 mole - x u
x=294u